Category: Bashrand

And then Nemo wanted weighted random numbers

Nemo then wanted weighted random numbers, so this item has been added to this page. The following script selects a random element from a weight list of options…



#!/bin/bash


# Copyright (c) Michael Still 2002

# Released under the terms of the GNU GPL


# In this case, Nemo wants to be able to specify a list of items, with

# weights associated with them…


# $1 is the list with weights, in the form:

# “1 frog 2 banana 3 hamster”


# Scary assumption number one, people hand me correctly formatted lists

# Incidentally, this will break with numbers exist in the items I am handed

# e.g. Banana42 will break this

NUMBERS=`echo $1 | sed ‘s/[^0-9 ]//g’`

WORDS=`echo $1 | sed ‘s/[0-9]//g’`

WEIGHTED=””


# Build the list of options, including the weights

for NUM in $NUMBERS

do

  WORD=`echo $WORDS | sed ‘s/ .*$//’`

  WORDS=`echo $WORDS | sed “s/^$WORD *//”`


  COUNT=0

  while [ $COUNT -lt $NUM ]

  do

    WEIGHTED=`echo “$WEIGHTED $WORD”`

    COUNT=$(( $COUNT + 1 ))

  done

done


# Get the random number

LOBOUND=1

HIBOUND=`echo $WEIGHTED | wc -w`

RANDMAX=32767

BINUMBER=$(( $LOBOUND + ($HIBOUND * $RANDOM) / ($RANDMAX + 1) ))


# Get the item — I can’t use shift, because it is not on the command line

COUNT=1

while [ $COUNT -lt $BINUMBER ]

do

  WEIGHTED=`echo $WEIGHTED | sed ‘s/^[^ ]*//’`

  COUNT=$(( $COUNT + 1 ))

done


# The first word should be magic selected one

echo $WEIGHTED | sed ‘s/ .*$//’

Getting a random number in bash

This script generates a bounded random number:



#!/bin/bash


# Generate a random number. Copyright (c) Michael Still 2002

# Released under the terms of the GNU GPL

#

# (Is it possible to copyright a single line of code?)


# To quote from the rand manpage as to why we bound the random number this way:

#

#       In Numerical Recipes in C: The Art of Scientific Computing

#       (William  H.  Press, Brian P. Flannery, Saul A. Teukolsky,

#       William T.  Vetterling;  New  York:  Cambridge  University

#       Press, 1992 (2nd ed., p. 277)), the following comments are

#       made:

#              “If you want to generate a random integer between 1

#              and 10, you should always do it by using high-order

#              bits, as in

#

#                     j=1+(int) (10.0*rand()/(RAND_MAX+1.0));

#

#              and never by anything resembling

#

#                     j=1+(rand() % 10);

#

#              (which uses lower-order bits).”


# To seed the random number generator, set RANDOM to a value… We can see

# that the bash code (2.05a in this case) already does some seeding for us…

#

# brand ()

# {

#  rseed = rseed * 1103515245 + 12345;

#  return ((unsigned int)((rseed >> 16) & 32767));       /* was % 32768 */

# }

#

# Here I have an example using the current time, which wont work well with

# multiple calls per second

#RANDOM=`date | tr -d “:” | cut -f 4 -d ” “`


# These variables just make the equation easier to read, and are not needed

LOBOUND=1

HIBOUND=10

RANDMAX=32767

BINUMBER=$(( $LOBOUND + ($HIBOUND * $RANDOM) / ($RANDMAX + 1) ))


echo $BINUMBER

Getting an arbitary item from a list

This script gets the specified element form the list on the command line…



#!/bin/bash


# Select a specified item from a list. Copyright (c) Michael Still 2002

# Released under the terms of the GNU GPL


# $1 is the number to get, $* except for $1 is the list of options, delimited

# by a space each


# We can the shift operation to get to the right number

shift $1

echo $1

The challenge and the result

So, I was at a CLUG meeting last night, and one of the speakers had a whole bunch of bash scripts for XDM theming. Anyway, he was using a perl script to generate the random selection of the theme elements, and me and my big mouth offered that it could be done in bash itself. So here we are…

Here’s my post to the CLUG mailing list the next day:



From mikal@stillhq.com Fri Mar 29 10:26:04 2002

Date: Fri, 29 Mar 2002 10:14:17 +1100 (EST)

From: Michael Still 

To: Linux user group 
Subject: Nemo’s bash challenge for the day


Well, I said it could be done…


The brief: Generate a random number, and then return that element from a

list of elements, in bash


The code: (Assuming that the arguements on the command line are the

possible return options, and that the random number generator is running

as a separate script)


LOBOUND=0

HIBOUND=$#

shift $(( $LOBOUND + ($HIBOUND * $RANDOM) / (32767 + 1) ))

echo $1


See the attachments for some exploratory scripts I wrote while coming up

with this truncated sh. There are 54 lines of comments / white spaces, to

the 4 or so lines of actual code.


Have a nice life…


Cheers,

Mikal


PS: How good is the bash random? See the attachment output.count for a

summary of 100,000 numbers between 1 and 10 being generated with the

default seed. It’s probably good enough for most people.


PPS: If you want the code, it should also be online at

http://www.stillhq.com/cgi-bin/getpage?area=bashrand&page=index.htm in

about 30 minutes, depending when Andrew goes to sleep.


—


Michael Still (mikal@stillhq.com)     UMT+11hrs


    [ Part 2, “”  Application/X-SH  2.1KB. ]

    [ Unable to print this part. ]


    [ Part 3, “”  Application/X-SH  412bytes. ]

    [ Unable to print this part. ]


    [ Part 4, “”  Text/PLAIN (Name: “output.count”)  2 lines. ]

    [ Unable to print this part. ]

I have included some explaination of the development process I went through below for those who are interested…